(1/6)^p=36^-p^-1

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Solution for (1/6)^p=36^-p^-1 equation: 



(1/6)^p=36^-p^-1

We move all terms to the left:

(1/6)^p-(36^-p^-1)=0



Domain of the equation: 6)^p!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

(+1/6)^p-(36^-p^-1)=0

We get rid of parentheses

(+1/6)^p+p^+1-36^=0

We multiply all the terms by the denominator


(+1+p^*6)^p+1*6)^p-36^*6)^p=0

Wy multiply elements

36p^2+(+1+p^*6)^p=0

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